Bonding

Coordinate (Dative Covalent) Bonds

Learn how coordinate bonds form when one atom donates both electrons in a shared pair. Explore examples in ammonium ions, BF₃·NH₃ adducts, transition metal complexes, and CO.

V
Vectora Team
STEM Education
9 min read
2026-01-14
·Updated 2026-03-27

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What Is a Coordinate Bond?

A coordinate bond (also called a dative covalent bond) is a covalent bond in which both electrons in the shared pair come from the same atom. The atom that donates is called the donor (Lewis base); the atom that accepts is called the acceptor (Lewis acid).

Once formed, a coordinate bond is identical in strength and length to an ordinary covalent bond — the distinction is only in how it was formed.

Learning Goals: By the end of this guide, you should be able to:

  1. Define a coordinate bond and distinguish it from a regular covalent bond.
  2. Identify the donor (Lewis base) and acceptor (Lewis acid) in examples.
  3. Draw coordinate bonds using the arrow notation (→).
  4. Recognise coordinate bonds in NH4+NH_4^+, H3O+H_3O^+, BF3⋅NH3BF_3·NH_3, [Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}, and CO.

How Coordinate Bonds Form

Requirements

ComponentRoleRequirement
Donor (Lewis base)Provides both electronsMust have a lone pair
Acceptor (Lewis acid)Receives the electron pairMust have an empty orbital

Arrow Notation

Coordinate bonds are drawn with an arrow (→) pointing from the donor to the acceptor:

:NH3→BF3:NH_3 \rightarrow BF_3

The arrow shows that nitrogen donates its lone pair into boron's empty p orbital.


Classic Examples

1. Ammonium Ion (NH4+NH_4^+)

NH3+H+→NH4+NH_3 + H^+ \rightarrow NH_4^+
  • Donor: NH3NH_3 (lone pair on N)
  • Acceptor: H+H^+ (empty 1s orbital)
  • Result: 4 equivalent N-H bonds (3 ordinary + 1 coordinate, but all identical once formed)

2. Hydronium Ion (H3O+H_3O^+)

H2O+H+→H3O+H_2O + H^+ \rightarrow H_3O^+
  • Donor: H2OH_2O (lone pair on O)
  • Acceptor: H+H^+ (empty orbital)

3. BF₃·NH₃ Adduct

BF3+:NH3→F3B←NH3BF_3 + :NH_3 \rightarrow F_3B \leftarrow NH_3
  • Boron has only 6 electrons (electron-deficient)
  • Nitrogen donates its lone pair into boron's empty 2p orbital
  • Boron achieves an octet; the adduct is much more stable

4. Carbon Monoxide (CO)

CO has a triple bond: one σ bond, one standard π bond, and one coordinate π bond where oxygen donates a lone pair to carbon. This gives carbon a lone pair, making CO an excellent ligand for transition metals.

5. Transition Metal Complexes

Cu2++6H2O→[Cu(H2O)6]2+Cu^{2+} + 6H_2O \rightarrow [Cu(H_2O)_6]^{2+}

Each water molecule donates a lone pair from O into empty d/hybrid orbitals on Cu2+Cu^{2+}. These are six coordinate bonds, forming the hydrated copper(II) ion.

ComplexLigandDonor atomCoordination number
[Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}H2OH_2OO6
[Fe(CN)6]4−[Fe(CN)_6]^{4-}CN−CN^-C6
[Ag(NH3)2]+[Ag(NH_3)_2]^+NH3NH_3N2
[CuCl4]2−[CuCl_4]^{2-}Cl−Cl^-Cl4

Worked Examples

Example 1: Identify the Coordinate Bond

Question: In PCl4+PCl_4^+, identify the coordinate bond.

Answer: Phosphorus normally forms 3 bonds in PCl3PCl_3 using 3 unpaired electrons. The fourth bond to Cl+Cl^+ is coordinate — P donates a lone pair to the empty orbital on Cl+Cl^+.

Example 2: Why Does BF3BF_3 Form an Adduct with NH3NH_3?

BF3BF_3 is electron-deficient (6 electrons on B). As a Lewis acid, it accepts the lone pair from NH3NH_3 (Lewis base). The coordinate bond gives boron a full octet, stabilising the molecule.

Example 3: Aluminium Chloride Dimer

AlCl3AlCl_3 dimerises to Al2Cl6Al_2Cl_6. Each monomer acts as both donor and acceptor: a Cl on one AlCl3AlCl_3 donates a lone pair into the empty orbital of the Al on the other AlCl3AlCl_3, forming two bridging coordinate bonds.


Common Mistakes

  1. Thinking coordinate bonds are weaker — Once formed, they are identical to ordinary covalent bonds. Bond strength and length are the same.

  2. Drawing the arrow backwards — The arrow points FROM the donor TO the acceptor. N→BN \rightarrow B means nitrogen donates to boron.

  3. Forgetting coordinate bonds in polyatomic ions — NH4+NH_4^+ and H3O+H_3O^+ both contain coordinate bonds. Examiners specifically ask about this.

  4. Confusing with ionic bonds — A coordinate bond is still a shared pair of electrons. The donor doesn't lose the electrons — they are shared.


Exam Tips (A-Level / AP / IB)

  • Use the arrow notation (→) in structural formulas to show coordinate bonds.
  • In NH4+NH_4^+, state: "All four N-H bonds are equivalent once formed — you cannot distinguish the coordinate bond experimentally."
  • Know the definition for full marks: "A covalent bond in which both electrons in the shared pair are donated by the same atom."
  • For transition metal complexes, name the ligand, donor atom, and coordination number.

Frequently Asked Questions

Can a coordinate bond be broken?

Yes, and when it breaks, both electrons return to the donor atom. For example, when NH4+NH_4^+ loses a proton, the lone pair returns to nitrogen.

Is a coordinate bond the same as a Lewis acid-base reaction?

Yes! Every coordinate bond formation is a Lewis acid-base interaction. The donor is the Lewis base; the acceptor is the Lewis acid.

Why is CO such a strong ligand?

CO can form coordinate bonds where C donates its lone pair to the metal (σ donation), and simultaneously accept electron density from metal d orbitals into its empty π* orbitals (π back-bonding). This synergistic bonding makes CO bind very strongly to transition metals.


References & Further Reading

This article was created by the Vectora Editorial Team and is reviewed for alignment with AP, IB, and A-Level curricula. Content is based on standard academic sources in chemistry, physics, biology, and mathematics.

Published: 2026-01-14 · Updated: 2026-03-27

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